Divisibility Test
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Practice questions:
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X = 1234…….616263. What will be the remainder if x is divided by 8 and 9 and 72?
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In above question if you add all digits till you get a single digit, what that digit will be?
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The six-digit number 73A998 is divisible by 6, How many values of A are possible?
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A hundred digit number is for med by writing first 54 natural numbers one after the other as 123456…………….5354. Find the remainder when this number is divided by 8.
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If 233 is divided by a certain number n it gives remainder 5. What will be the remainder 466 is divided by 2n assuming the quotient is same in both the cases.
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For which of the following values of n is (100 + n)/n NOT an integer ?
(A) 1 (B) 2 (C) 3 (D) 4
(E) 5
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If the remainder is 7 when positive integer n is divided by 18, what is the remainder when n is divided by 6 ?
(A) 0 (B) 1 (C) 2 (D) 3
(E) 4
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If M and N are positive integers that have remainders of 1 and 3, respectively, when divided by 6, which of the following could NOT be a possible value of M + N?
(A) 86 (B) 52 (C) 34 (D) 28
(E) 10
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When the integer n is divided by 17, the quotient is x and the remainder is 5. When n is divided by 23, the quotient is y and the remainder is 14. Which of the following is true?
(A) 23x + 17y = 19 (B) 17x – 23y = 9
(C) 17x + 23y = 19 (D) 14x + 5y = 6
(E) 5x – 14y = –6
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If when 950 and 1170 are divided by a natural number d, the remainders obtained are 18 and 5 respectively, then d is a t most
(A) 117 (B) 247 (C) 223 (D) 123
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pq, qr, qp and pp are two-digit numers, 'pqr' is a three-digit number and 'prrp' is a four-digit number (p, q, r are all numerals.) If pq x pr = pqr, then the remainder when (qp x prrp) is divided by 'pp' is
(A) 0 (B) 1
(C) 7 (D) None of these
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Given that a, b, c and d are positive integers such that b3/2 = a, and d5/4 = c. If b – d = 9. then find the value of (a – c).
(A) 92 (B) 94 (C) 95 (D) 93
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For how many values of n less than 17, n being a positive integer, is n! + (n + 1)! (n + 2)! an integral multiple of 49 ?
(A) 5 (B) 2 (C) 3 (D) 1