Motion Worksheet-9
A. 5 m/s2 B. 2 m/s2 C. 3.6 m/s2 D. 1 m/s2
A. 8 m/s B. 12 m/s C. 16 m/s D. 28 m/s
A. Distance traveled B. Velocity
C. Acceleration D. Displacement
A. M B. m2 C. m/s–1 D. m/s–2
A. Uniform velocity B. Uniform acceleration
C. Increasing acceleration D. Decreasing acceleration
A. Car A is faster than car D.
B. Car B is the slowest
C. Car D is mass faster than the car C
D. Car c is the slowest
A. 25 m/s–1 B. 40 m/s–1 C. 10 m/s–1 D. 250 m/s–1
A. +4 m/s–2 B. –4 m/s–2
C. +0.25 m/s2 D. –0.25 m/s2
A. Magnitude of acceleration being produced
B. Distance covered by the sprinter per second
C. Direction in which the sprinter is running
D. Centripetal force acting on the sprinter
A. ST B. QR C. RS D. PQ
Answer:
Explanation: Here u = 20 m/s
a = 4 m/s2
t = 2 sec
Putting the values in equation of motion
v = u + at
v = 20 + 4 × 2 = 28 m/s
Explanation: In speed time graph the distance travelled by the body in a given time is equal to the area between the speed time graph and the time axis. The unit of distance is meter or kilometer.
Explanation: Velocity will be constant,
Explanation: Here u = 20 m/s
v = 0 m/s ( motorcycle is coming to rest)
t = 5 sec
Put the values in equation of motion
v = u + at
0 = 20 + a × 5
A = - 4 m/s2
Here if we talk about acceleration it will be negative but in the question deceleration is asked so it will be positive.